How many moles of NH3 from when 32.4 L of H2 gas completely reacts at STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP

N₂ (g) + 3H₂ (g) →2NH₃ (g)

ps: We have to not only give the answer which is 1.45 mol NH3 but we have to show the equation of how we got to it.

Question

Cheyenne Clarke

11 October, 17:43

+2

Answers (1)

Know the Answer?

Alexandra Armstrong · Answer 1

N_2 (g) + 3H_2 (g) rightarrow 2NH_3 (g) volume of H_2 = 32.44 At STP 1 mole of H_2 = 22.4L? mole of H_2 = 32.4L therefore moles of H_2