What is the volume of 0.24 mol oxygen (O2) gas at 345 K and a pressure of 0.75 atm

We know that the ideal gas equation relates the pressure, volume, temperature, and moles of gases as:

PV = nRT

This is a combined gas law based on other gas law like Boyle's law, Charle's law, Avagadro's law, Gay Lussac's law

P = pressure = 0.75 atm

V = volume = ?

n = moles = 0.24 mol

R = 0.0821 L atm / molK [gas constant]

T = temperature = 345 K

Putting the values

Volume = nRT / P

Volume = 0.24 X 0.0821 X 345 / 0.75 = 9.06 L