How many moles of gas are present if p=11 atm, V=12L, T=185k?

8.69 mol.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 11.0 atm).

V is the volume of the gas in L (V = 12.0 L).

n is the no. of moles of the gas in mol (n = ? mol).

R is the general gas constant (R = 0.0821 L. atm/mol. K),

T is the temperature of the gas in K (T = 185.0 K).

∴ n = PV/RT = (11.0 atm) (12.0 L) / (0.0821 L. atm/mol. K) (185.0 K) = 8.69 mol.