Calculate the standard entropy of reaction at 298 K for the reaction Hg (liq) + Cl2 (g) → HgCl2 (s) The standard molar entropies of the species at that temperature are: Sºm (Hg, liq) = 76.02 J / (K mol); Sºm (Cl2, g) = 223.07 J / (K mol); Sºm (HgCl2, s) = 146.0 J / (K mol)

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Chemistry

Hadley Lindsey

21 June, 06:47

Calculate the standard entropy of reaction at 298 K for the reaction Hg (liq) + Cl2 (g) → HgCl2 (s) The standard molar entropies of the species at that temperature are: Sºm (Hg, liq) = 76.02 J / (K mol); Sºm (Cl2, g) = 223.07 J / (K mol); Sºm (HgCl2, s) = 146.0 J / (K mol)

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Briana · Answer 1

-153.1 J / (K mol)

Explanation:

Calculate the standard entropy of reaction at 298 K for the reaction Hg (liq) + Cl2 (g) → HgCl2 (s) The standard molar entropies of the species at that temperature are: Sºm (Hg, liq) = 76.02 J / (K mol); Sºm (Cl2, g) = 223.07 J / (K mol); Sºm (HgCl2, s) = 146.0 J / (K mol)

Hg (liq) + Cl2 (g) → HgCl2 (s)

Given that;

The standard molar entropies of the species at that temperature are:

Sºm (Hg, liq) = 76.02 J / (K mol);

Sºm (Cl2, g) = 223.07 J / (K mol);

Sºm (HgCl2, s) = 146.0 J / (K mol)

The standard molar entropies of reaction = Sºm[products] - Sºm [ reactants]

= 146.0 J / (K mol) - [76.02 J / (K mol) + 223.07 J / (K mol) ]

= - 153.09 J / (K mol)

= or - 153.1 J / (K mol)

Hence the answer is - 153.1 J / (K mol)