Ask Question
8 March, 07:06

A marshmallow has an initial volume of 0.033 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.439L, what is the pressure inside the chamber?

+1
Answers (1)
  1. 8 March, 10:30
    0
    0.075 atm

    Explanation:

    P1V1 = P2V2

    1.0 atm * 0.033L = P2 * 0.439 L

    P2 = 1*0.033/0.439 = 0.075 atm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A marshmallow has an initial volume of 0.033 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers