Students working in lab use 52.3g of CaCl2 to make a solution. When the solution is brought to a final volume of 800. mL, what is the concentration?

A. 0.139 M

B. 0.153 M

C. 0.588 M

D. 0.632 M

The answer is C:.588 M

Explanation:

[CaCl2] = mols CaCl2/Liters of solution

molar mass of CaCl2 = 110.98 g / 1 mole (from periodic table)

800 mL/1000 mL =.8 Liters of solution

1)

52.3g CaCl2 / 110.98g =.47 mole

2)

.47 mole/.8 L =.589 M

So the answer is C