What is the mole ratio of PbO2 to water?

PbO, H, 0 = 1:0

The mole ratio of PbO2 to H2O is 1 : 2.

Explanation:

The balanced reaction equation is:

Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O

On the reactant side, we have 1 mole of Pb, 1 mole of PbO2, 2 moles of H2SO4.

On the product side, we have 2 moles of PbSO4 and 2 moles of H2O.

This means that for ever 1 mole of PbO2 consumed, 2 moles of water is formed as product.

Hence, the mole ratio of PbO2 to H2O is 1 : 2.