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19 April, 04:51

N2 + 3H2 → 2NH3 What volume of ammonia at STP is produced if 30.0 g of nitrogen gas is reacted with an excess of hydrogen gas?

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  1. 19 April, 07:59
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    V = 48L

    Explanation:

    Moles of N2 = m/M = 30/28 = 1.07moles

    From the equation of reaction

    N2 + 3H2 → 2NH3

    1mole of N2 produces 2mole of NH3

    Hence

    1.07moles will produce 1.07*2 = 2.14 moles

    At STP, 1mole occupy 22.4L

    Hence volume of N2 produced = 2.14*22.4 = 48 L
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