What mass of magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?

3.39g of MgBr

Explanation:

Reaction between magnesium and bromine

Mg + Br₂ → MgBr

Mass of MgBr = ?

1g of Mg + 5.0g of Br₂

6g of Mg and Br₂

Molar mass of Mg = 24g/mol

Molar mass of Br = 80g/mol

Number of moles = mass / molar mass

Mass = number of moles * molarmass

Mass of Mg = 1 * 24 = 24g

Mass of Br₂ = 1 * (2*80) = 160g (diatomic molecule)

Molarmass of MgBr = (24 + 80) = 104g/mol

Mass of MgBr = 1 * 104 = 104g/mol

24g of Mg + 160g of Br₂ = 104g of MgBr

184g of (mg and Br) = 104g of mgBr

6g of (mg and Br) = y g of MgBr

y = (6 * 104) / 184

y = 3.39g of MgBr