A gas has a volume of 3 L at a temperature of 78 c. Find the volume of the gas at standard temperature

The answer to your question is V2 = 2.5 l

Explanation:

Data

Volume 1 = V1 = 3 l

Temperature 1 = T1 = 78°C

Volume 2 = V2 = ?

Temperature 2 = T2 = 20°C Standard temperature = 20°C

Process

To solve this problem use Charles' law

V1/T1 = V2/T2

-Solve for V2

V2 = V1T2 / T1

1. - Convert the temperature to °K

T1 = 78 + 273 = 352°K

T2 = 20 + 273 = 293°K

2. - Substitution

V2 = (3 x 293) / 352

3. - Simplification

V2 = 879/352

4. - Result

V2 = 2.5 l