What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Br2 (l) and I - (aq) Use the reduction potential values for Br2 (l) of 1.07 V and for I2 (s) of 0.53 V Give your answer using E-notation with NO decimal places (e. g., 2 x 10-2 would be 2E-2; and 2.12 x 10-2 would also be 2E-2.). Do NOT include spaces, units, punctuation or anything else silly!

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Chemistry

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30 April, 02:53

What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Br2 (l) and I - (aq) Use the reduction potential values for Br2 (l) of 1.07 V and for I2 (s) of 0.53 V Give your answer using E-notation with NO decimal places (e. g., 2 x 10-2 would be 2E-2; and 2.12 x 10-2 would also be 2E-2.). Do NOT include spaces, units, punctuation or anything else silly!

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Janelle Zamora · Answer 1

1.58*10E18

Explanation:

Since we have the reduction potentials we could make decisions regarding which one will be the anode or cathode. Evidently, bromine having the more positive reduction potential will be the cathode while the iodine will be the anode.

E°cell = 1.07 - 0.53 = 0.54 V

E°cell = 0.0592/n logK

0.54 = 0.0592/2 logK

logK = 0.54/0.0296

logK = 18.2

K = Antilog (18.2)

K = 1.58*10^18