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30 October, 07:02

What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K

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  1. 30 October, 07:56
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    1.67 atm.

    Explanation:

    We can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm (P = ? atm).

    V is the volume of the gas in L (V = 5.0 L).

    n is the no. of moles of the gas in mol (n = 0.5 mol).

    R is the general gas constant (R = 0.0821 L. atm/mol. K),

    T is the temperature of the gas in K (T = 203 K).

    ∴ P = nRT/V = (0.5 mol) (0.0821 L. atm/mol. K) (203 K) / (5.0 L) = 1.67 atm.
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