Which of the following sets of empirícal formula, molar mass, and molecular formula is correct?

The option C is correct. CH4N, 90g, C3H12N3.

Explanation:

Option C:

The molecular formula is C3H12N3. If we take ratio 3:12:3 that will be equal to 1:4:1 so its empirical formula will be CH4N. The molar mass of molecular formula = (12*3) + (1*12) + (14*3) = 98 g

Option A:

In option A, molecular and empirical formula are both correct but molar mass is not valid. It should be 169 acc. to molecular formula.

Option B:

In option B, molecular formual is not valid. It should be as C6H16O2