Describe how you would prepare 500.0mL of an aqueous solution that is 30.0% isopropyl alcohol by volume

The solution can be prepared by adding 150.0 mL of isopropyl alcohol to 350.0 mL of water to make 30.0% isopropyl alcohol aqueous solution.

Explanation:

∵ The volume% of a solution = [ (volume of the solute (isopropy) / (volume of the solution) ] x 100.

The volume % = 30.0%, volume of the solution = 500.0 mL.

∴ Volume of the solute = (the volume% of a solution) (volume of the solution) / 100 = (30.0%) (500.0 mL) / 100 = 150.0 mL.

∵ The volume of solution = volume of the solute + volume of water

∴ Volume of water = volume of the solution - volume of the solute = (500.0 mL) - (350.0 mL) = 150.0 mL.

So, the solution can be prepared by adding 150.0 mL of isopropyl alcohol to 350.0 mL of water to make 30.0% isopropyl alcohol aqueous solution.