Ask Question
7 June, 10:09

In your lab you are studying the kinetics of the degradation of a pain killer in the human liver. You are monitoring the concentration of the pain killer over a period of time. The initial concentration of the pain killer in your experiment was 1.59 M. After 0.80881 hours the concentration was found to be 0.795 M. In another 0.80881 hours the concentration was found to be 0.3975 M (t=27.868 hours overall).

If another experiment were set up where the initial concentration of the pain killer was 0.479 M, how long would it take for the pain killer concentration to reach 0.0161 M?

+4
Answers (1)
  1. 7 June, 12:16
    0
    From the data it is clear that after each. 80881 hours, the concentration becomes half. so its decomposition appears to be first order.

    k = 1 / t ln A₀ / A

    = (1/.80881) ln 2

    =.857

    for the given case

    A =.0161, A₀ =.479

    t = ?

    t = 1/k ln (.479 /.0161)

    = (1 /.857) ln (.479 /.0161)

    = (1 /.857) x ln 29.75

    = 3.959 hours
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “In your lab you are studying the kinetics of the degradation of a pain killer in the human liver. You are monitoring the concentration of ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers