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9 November, 11:21

You make an iron (II) sulfate solution with a molarity of 2.1 M. If the solution is 500 mL total, how many grams of iron (II) sulfate is that?

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  1. 9 November, 12:15
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    2.1>1000

    ?>500

    (500*2.1) : 1000=1.05moles

    Mass = molesx molar mass

    1.05 * (56+32 + (16*4))

    1.05*152=159.6g
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