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28 April, 16:17

At 850 K, the equilibrium constant for the reaction

2SO2 (g) + O2 (g) ⇌2SO3 (g) Kc=15.

If the given concentrations of the three gases are mixed, predict in which direction the net reaction will proceed toward equilibrium. Left No net reaction Right

a. [SO2] = 0.60 M, [O2] = 0.70 M, [SO3] = 0.16 M

b. [SO2] = 0.20 M, [O2] = 0.60 M, [SO3] = 0.60 M

c. [SO2] = 0.10 M, [O2] = 0.20 M, [SO3] = 0.40 M

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  1. 28 April, 19:07
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    a) Q
    b) Q=Kc the reaction is at the equilibrium

    c) Q>Kc the reaction will shift to the left

    Explanation:

    Step 1: Data given

    temperature = 850 K

    Kc = 15

    When Q=K, the system is at equilibrium. Since the system is already at equilibrium, there will no shift to left or right happen.

    When Q>K, it means we have more products than reactants. As reaction, the amount of products will decrease, and produce more reactants. in other words, the reaction will shift to the left.

    When Q
    Step 2: The balanced equation

    2SO2 (g) + O2 (g) ⇌2SO3 (g) Kc=15

    Step 3: Calculate Q

    Q = [SO3]²/[O2][SO2]²

    a. [SO2] = 0.60 M, [O2] = 0.70 M, [SO3] = 0.16 M

    Q = 0.16²/0.70*0.60²

    Q = 0.10

    Q << Kc

    we have more reactants than products. As reaction, the amount of reactants will decrease, and will produce more products. In other words, the reaction will shift to the right.

    b. [SO2] = 0.20 M, [O2] = 0.60 M, [SO3] = 0.60 M

    Q = 0.60²/0.60*0.20²

    Q = 15

    Q=K, the system is at equilibrium. Since the system is already at equilibrium, there will no shift to left or right happen.

    c. [SO2] = 0.10 M, [O2] = 0.20 M, [SO3] = 0.40 M

    Q = 0.40²/0.20*0.10²

    Q = 80

    Q>K, it means we have more products than reactants. As reaction, the amount of products will decrease, and produce more reactants. in other words, the reaction will shift to the left.
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