The reaction of 7.8 g benzene, C6H6, with excess HNO3 resulted in

0.90 g of H20. What is the percentage yield?

C6H6 + HNO3 - C6H5NO2 + H2O

Molar Mass: C6H6 = 78 g/mol; HNO3 = 63 g/mol; C6H5NO2 = 123

g/mol; H2O = 18 g/mol

Question

Cornelius Hoffman

6 August, 14:33

+2

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Chanel Guerra · Answer 1

Molar más: C6H6 = 78 g/mol; HNO3 = 63g / mol; C6H5NO2 = 123

The reaction of 7.8 g benzene, C6H6, with excess HNO3 resulted in0.90 g of H20. What is the percentage yield?C6H6 + HNO3 - C6H5NO2 + H2OMolar Mass: C6H6 = 78 g/mol; HNO3 = 63 g/mol; C6H5NO2 = 123g/mol; H2O = 18 g/mol