What quantity of gas, in moles, is contained in 26.97L at STP?

The answer to your question is 1.09 moles

Explanation:

Data

Volume = 26.97 l

Temperature = 20°C

Pressure = 1 atm

Gas constant = 0.082 atm l / mol°K

Process

1. - Convert temperature to °K

Temperature = 26.97 + 273

= 299.97°K

2. - Write the formula

PV = nRT

-solve for moles

n = PV / RT

-substitution

n = (1 x 26.97) / (0.082 x 299.97)

-Simplification

n = 26.97 / 24.6

-Result

n = 1.09