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26 August, 05:41

What pressure would it take to compress 300. L Of Helium at 1.00atm into a 2.00 L tank at constant temperature

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  1. 26 August, 05:52
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    150 atm

    Explanation:

    Given dа ta:

    Initial volume = 300 L

    Initial pressure = 1 atm

    Final volume = 2.00 L

    Final pressure = ?

    Solution:

    The given problem will be solved through the Boly's law,

    "The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

    Mathematical expression:

    P₁V₁ = P₂V₂

    P₁ = Initial pressure

    V₁ = initial volume

    P₂ = final pressure

    V₂ = final volume

    Now we will put the values in formula,

    P₁V₁ = P₂V₂

    1 atm * 300 L = P₂ * 2.00 L

    P₂ = 300 atm. L / 2.00 L

    P₂ = 150 atm
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