Predict the products of each reaction: Part A Part complete HClO4 (aq) + Fe2O3 (s) → Express your answer as a balanced chemical equation. Identify all of the phases in your answer. 6HClO4 (aq) + Fe2O3 (s) →2Fe (ClO4) 3 (aq) + 3H2O (l) Previous Answers Correct Part B H2SO4 (aq) + Sr (s) → Express your answer as a balanced chemical equation. Identify all of the phases in your answer. Request Answer Part C H3PO4 (aq) + KOH (aq) → Express your answer as a balanced chemical equation. Identify all of the phases in your answer. nothing Request Answer Provide Feedback Correct. No additional followup.

Part A: 6HClO₄ (aq) + Fe₂O₃ (s) → 2Fe (ClO₄) ₃ (aq) + 3H₂O (l).

Part B: H₂SO₄ (aq) + Sr (s) → SrSO₄ (s) + H₂ (g).

Part C: H₃PO₄ (aq) + 3KOH (aq) → K₃PO₄ (aq) + 3H₂O (l).

Explanation:

Part A: complete HClO₄ (aq) + Fe₂O₃ (s) → Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

The balanced chemical equation is:

6HClO₄ (aq) + Fe₂O₃ (s) → 2Fe (ClO₄) ₃ (aq) + 3H₂O (l).

It is clear that 6 mol of HClO₄ (in aqueous phase) react with 1 mol of Fe₂O₃ (in solid phase) to produce 2 mol of Fe (ClO₄) ₃ (in aqueous phase) and 3 mol of H₂O (in liquid phase).

Part B: H₂SO₄ (aq) + Sr (s) → Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

The balanced chemical equation is:

H₂SO₄ (aq) + Sr (s) → SrSO₄ (s) + H₂ (g).

It is clear that 1 mol of H₂SO₄ (in aqueous phase) reacts with 1 mol of Sr (in solid phase) to produce 1 mol of SrSO₄ (in solid phase) and 1 mol of H₂ (in gas phase).

Part C: H₃PO₄ (aq) + KOH (aq) → Express your answer as a balanced chemical equation.

The balanced chemical equation is:

H₃PO₄ (aq) + 3KOH (aq) → K₃PO₄ (aq) + 3H₂O (l).

It is clear that 1 mol of H₃PO₄ (in aqueous phase) react with 3 mol of KOH (in aqueous phase) to produce 1 mol of K₃PO₄ (in aqueous phase) and 3 mol of H₂O (in liquid phase).