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17 July, 09:32

Cyclohexene, a hydrocarbon, has a molar mass of 82.1 g/mole. if the combustion of 0.8300 g cyclohexene produces 0.9102 g h2o and 2.668 g co2, what is the molecular formula of this compound?

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  1. 17 July, 10:43
    0
    The molecular formula will be C6H10.

    Explanation;

    Given dа ta:

    mass of compound = 0.8300 g mass of H2O = 0.9102 g mass of CO2 = 2.668 g

    Solution:

    % of C = (mass of CO2/mass of compound) * (12/44) * 100

    % of C = (2.66:0.8300) * (12/44) * 100 = 87.40 %

    % of H = (mass of H2O/mass of compound) * (2/18) * 100

    % of H = (0.910:0.8300) * (2/18) * 100 = 12.18 %

    Niiw we calculate moles of C and H from % as follow

    moles of C = 87.40/12 = 7.2 mol

    moles of H = 12.18/1 = 12.18 mol

    In we take atomic ratio

    C : H

    12.18/7.2 : 7.2/7.2

    1.69 : 1

    multiply atomic ratio by 3 to get whole no.

    C : H = 3 (1.69:1) = 5 : 3

    So empirical formula is C3H5.

    Calculations of molecular formula:

    empirical formula mass of C3H5 = 41

    n = molar mass of compound / empirical formula mass

    n = 82.1/41 = 2

    Molecular mass = n * empirical formula = 2 * C3H5 = C6H10
  2. 17 July, 11:04
    0
    Answer is: the molecular formula is C₆H₁₀.

    Chemical reaction: C₆Hₓ + yO₂ → 6CO₂ + x/2H₂O.

    m (H₂O) = 0.9102; mass of the water.

    n (H₂O) = m (H₂O) : m (H₂O)

    n (H₂O) = 0,9102 g : 18 g/mol

    n (H₂O) = 0,0505 mol.

    From chemical reaction: n (H) = 2 · n (H₂O).

    n (H) = 0.101 mol.

    m (CO₂) = 2.668 g; mass of carbon dioxide.

    n (CO₂) = 2.668 g : 44 g/mol.

    n (CO₂) = 0.0606 mol; amount of the substance.

    n (CO₂) = n (C) = 0.0606 mol.

    n (C) : n (H) = 0.606 mol : 0.101 mol.

    n (C) : n (H) = 6 : 10; proportion of carbon and hydrogen atoms in cyclohexene.
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