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28 June, 00:36

If 89.6 joules of heat 20.0 grams of iron from 30.0 C to 40.0 C, what is the specific heat of the iron in J/g. C?

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  1. 28 June, 03:35
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    H = m c ΔT

    89.6 J = (20.0 g) * c * (40.0 - 30.0) °C

    Specific heat of iron, c = 89.6 / [20.0 * (40.0 - 30.0) ] J / (g°C) = 0.448 J / (g°C)
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