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7 August, 09:13

If 0.545J of heat leads to a 0.892 degree C change, what mass of water is present?

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  1. 7 August, 12:35
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    I got. 146 g of water

    Explanation:

    Refer to this equation:

    Q = mcΔt

    Q=.545 J

    c = 4.186 J/g

    Δt=.892

    plug in values:

    .545 J = m (4.186 J/g) (.892°C)

    simplify:

    .545 J = m (3.734 J/g°C)

    .146 g
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