Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +

2PO2 (aq)

Question

Chemistry

Newt

23 February, 04:05

Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +

2PO2 (aq)

+5

Answers (1)

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Zackary Oneal · Answer 1

Kc = [Pb²⁺]³.[PO₄³⁻]²

Explanation:

Let's consider the following reaction at equilibrium.

Pb₃ (PO₄) ₂ (s) ⇄ 3 Pb²⁺ (aq) + 2 PO₄³⁻ (aq)

The concentration equilibrium constant is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.

Kc = [Pb²⁺]³.[PO₄³⁻]²

This equilibrium constant is known as the solubility product of Pb₃ (PO₄) ₂.

Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +2PO2 (aq)

Write the equilibrium constant: Pb3 (PO4) 2 (s) = 3Pb2 + (aq) +

2PO2 (aq)