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3 April, 03:42

How many moles of NaCl are present in 1.63 liters of a 0.954 M solution?

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Answers (1)
  1. 3 April, 05:52
    0
    1.56 mol

    Explanation:

    c = n/V Multiply both sides by V and transpose

    n = Vc

    c = 0.954 mol·L⁻¹

    V = 1.63 L Calculate the moles

    n = 0.954 * 1.63

    n = 1.56 mol
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