How many grams HBr will be produced from 0.100 moles bromine reacted with excess hydrogen?

16.18 g HBr

Explanation:

We are given;

0.100 moles of Bromine

We need to determine the amount of HBr produced when bromine reacts with hydrogen;

First, we write the equation for the reaction;

H₂ (g) + Br₂ (l) → 2HBr

From the equation;

1 mole of bromine reacts with hydrogen to form 2 moles of HBr

Therefore;

Moles of HBr = 2 * moles of Bromine

= 2 * 0.100 moles

= 0.200 moles

Secondly, we determine the mass of HBr produced

Mass = Number of moles * molar mass

Molar mass of HBr = 80.91 g/mol

Thus;

Mass of HBr = 0.200 moles * 80.91 g/mol

= 16.182 g

= 16.18 g

Therefore, the mass of HBr is 16.18 g