14. A 35.0 mL sample of argon gas has a pressure of 1.0 atm and a temperature of 150 C. What is the final volume if the pressure goes to 2.0 atm and the temperature to 450 C?

The answer to your question is V2 = 29.9 ml

Explanation:

Data

Volume 1 = V1 = 35 ml

Pressure 1 = P1 = 1 atm

Temperature 1 = T1 = 150°C

Volume 2 = V2 = ? ml

Pressure 2 = P2 = 2 atm

Temperature 2 = T2 = 450 °C

Process

1. - Convert temperature to °K

Temperature 1 = 150 + 273 = 423°K

Temperature 2 = 450 + 273 = 723°K

2. - Use the Combined gas law to find the volume

P1V1/T1 = P2V2/T2

-Solve for V2

V2 = P1V1T2 / T1P2

-Substitution

V2 = (1 x 35 x 723) / (423 x 2)

-Simplification

V2 = 25305 / 846

-Result

V2 = 29.9 ml