Ba (oh) 2 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.750 m ba (oh) 2 solution.

The concentration of each of the individual ions in a 0750 M Ba (OH) 2 solution is

[Ba2+] = 0.750 M

[OH-] = 1.50 M

calculation

write the equation for dissociation

that is Ba (OH) 2 (s) → Ba2 + (aq) + 2OH - (aq)

by use of mole ratio of Ba (OH) 2 : Ba2 + which is 1: 1 the concentration of Ba2 + is therefore = 0.750M

by use of mole ratio of Ba (OH) 2 : OH - which is 1:2 the concentration of OH - = 0.750 M x2/1=1.50 M