Ask Question
15 August, 17:22

A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solution is first prepared by dissolving 16.8 mg of fluoxymesterone in enough water to give a total volume of 500.0 ml. a 1.0 μl aliquot (portion) of this stock solution is taken out and then diluted to a final volume of 1.0 ml. calculate the final concentration of this new solution in m.

+5
Answers (1)
  1. 15 August, 20:43
    0
    The concentration of new solution will be 1*10∧-7 M.

    Solution:

    Data Given

    given mass of fluoxymesterone = 16.8mg = 0.0168 g

    molar mass of fluoxymesterone = 336g/mol

    vol. of fluoxymesterone = 500.0 ml = 0.500 L

    Stock Molarity of fluoxymesterone = (0.0168/336) : 0.500 = 1*10∧-4 M

    So applying dilution formula

    Stock Solution : New Solution

    M1. V1 = M2. V2

    (1*10∧-4 M) * (1*10∧-6 L) = M2 * 0.001 L

    [ (1*10∧-4) * (1*10∧-6) ]:[0.001] = M2

    1 * 10∧-7 = M2

    Result:

    The concentration of new solution M2 will be 1 * 10∧-7
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solution is first ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers