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29 December, 03:44

For the reaction below, identify the excess reactant when 4.35 g of hydrogen reacts with 30.75 g of iodine to produce hydrogen iodide.

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  1. 29 December, 05:26
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    The excess reactant when 4.35 g of hydrogen reacts with 30.75g of hydrogen iodide is hydrogen

    calculation

    write the equation for the reaction

    H2 (g) + I2 (g) → 2HI (g)

    find the mole of each reactant

    moles = mass/molar mass

    moles of H2 = 4.35 g/2 g/mol = 2.175 moles

    moles o I2 = 30.75 g / 254 g/mo=0.1211 moles

    0.1211 moles of I2 reacted with 0.1211 moles of H2 but there are more moles of H2 there Hydrogen was in excess
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