Vanadium (v) oxide reacts with calcium according to the chemical equation below. when 10.0 mole of v2o5 are mixed with 10.0 mole of ca, which is the limiting reagent?

The limiting agent has due to following properties:

I. It completely reacted in the reaction.

II. It determines the amount of the product in mole.

The general reaction between Vanadium (v) oxide and Ca is as follows:

V2O5 (s) + 5Ca (l) = 2V (l) + 5CaO (s)

Given that mole of V2O5 (s) = 10.0 mole

Mole of Ca = 10.0 mole

10.0 mole Ca * 1 mole V2O5 / 5 mole Ca

= 2 mole V2O5

Hence used V2O5 is 2 mole, and Ca is completely used. thus here Ca is limiting agent and V2O5 is present in excess (10-2 = 8 mole)