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18 November, 08:46

How many grams are there in 9.03x10^23 molecules of CO2?

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  1. 18 November, 09:43
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    66g

    Explanation:

    A background knowledge of Avogadro's hypothesis proved that 1mole of any substance contains 6.02x10^23 molecules.

    From the above findings, we discovered that 1 mole of CO2 also contains 6.02x10^23 molecules.

    1 mole of CO2 = 12 + (2x16) = 12 + 32 = 44g

    Now we can obtain the mass of CO2 that contains 9.03x10^23 molecules as follow:

    44g of CO2 contains 6.02x10^23 molecules.

    Therefore, Xg of CO2 will contain 9.03x10^23 molecules i. e

    Xg of CO2 = (44x9.03x10^23) / 6.02x10^23 = 66g

    Therefore, 66g of CO2 contains 9.03x10^23 molecules
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