A 4.00 L sample of a gas is heated from 20.0 K to 200.0 K. What will its final volume be?

40L

Explanation:

The following were obtained from the question:

V1 (initial volume) = 4L

T1 (initial temperature) = 20K

T2 (final temperature) = 200K

V2 (final volume) = ?

Using the equation V1 / T1 = V2/T2, the final volume of the gas can easily be obtain as follow:

V1 / T1 = V2/T2

4/20 = V2/200

Cross multiply to express in linear form as shown below:

20 x V2 = 4 x 200

Divide both side by 20

V2 = (4 x 200) / 20

V2 = 40L

The final volume of the gas is 40L