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19 April, 21:35

Synthetic diamonds can be manufactured at pressures of 6.00 x 104 atm. If we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure of 6.00 x 104 atm, what would the volume of that gas be?

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  1. 19 April, 22:27
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    The answer to your question is V1 = 3.3 x 10⁻⁵ l

    Explanation:

    Data

    Pressure 1 = P1 = 6 x 10⁴ atm

    Volume 1 = V1 = ?

    Pressure 2 = P2 = 1 atm

    Volume 2 = V2 = 2 l

    Process

    To solve this problem use Boyle's law

    P1V1 = P2V2

    -Solve for V1

    V1 = P2V2 / P1

    -Substitution

    V1 = (1) (2) / 6 x 10⁴

    -Simplification

    V1 = 2 / 6 x 10⁴

    -Result

    V1 = 3.3 x 10⁻⁵ l
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