Calculate the heat of reaction for the following reaction: h2 (g) + cl2 (g) (g) Round your answer to the nearest.

Given reaction:

H2 (g) + Cl2 (g) → 2HCl (g)

Formula:

Heat of the reaction is the enthalpy change given as:

ΔHrxn = ∑nΔH°f (products) - ∑nΔH°f (reactants)

= [2ΔH°f (HCl (g)) ] - [ΔH°f (H2 (g)) + ΔH°f (Cl2 (g)) ]

= [2 (-92.31) ] - [0 + 0] = - 184.62 kJ/mol

The heat of the reaction is - 184.62 kJ/mol