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24 February, 16:35

Calculate the ph of the solution 0.2M Mg (OH) 2

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Answers (2)
  1. 24 February, 16:49
    0
    Mg (OH) 2 is base

    Oh = 0.2 x 2 =.4

    Poh = - Log (.4)

    =.3979

    Ph + Poh = 14

    Ph = 14 -.3979

    = 13.60
  2. 24 February, 17:33
    0
    13.60 is the answer
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