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16 September, 17:35

What is the molarity of a solution that has 23.0 g of NaOH dissolved in 0.500 L of solution?

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  1. 16 September, 19:40
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    Answer: 1.15M

    Explanation:

    Given that,

    Amount of moles of NaOH (n) = ?

    Mass of NaOH in grams = 23.0g

    For molar mass of NaOH, use the atomic masses: Na = 23g; O = 16g; H = 1g

    NaOH = (23g + 16g + 1g)

    = 40g/mol

    Since, n = mass in grams / molar mass

    n = 23.0g / 40.0g/mol

    n = 0.575 mole

    Volume of NaOH solution (v) = 0.5 L

    Concentration of NaOH solution (c) = ?

    Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

    c = n / v

    c = 0.575 mole / 0.5L

    c = 1.15 M (M stands for molarity and gives the concentration in moles per litres)

    Thus, the molarity of the solution is 1.15M
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