If 1.0 liters of 0.40 M KOH are

diluted to 3.0 liters what is the

new concentration?

The new concentration is 0,13 M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We use the formula for dilutions:

C1 x V1 = C2 x V2

C2 = (C1 x V1) / V2

C2 = (0,40 M x 1,0 L) / 3,0L

C2 = 0,13 M