How many moles are in 92.2 g Fe2O3?

Answer: 0.58 moles

Explanation:

Given that,

Amount of moles of Fe2O3 (n) = ?

Mass of Fe2O3 in grams = 92.2g

For molar mass of Fe2O3, use the atomic masses:

Iron, Fe = 56g;

Oxygen, O = 16g

Fe2O3 = (56g x 2) + (16g x 3)

= 112g + 48g

= 160g/mol

Since, amount of moles = mass in grams / molar mass

n = 92.2g / 160g/mol

n = 0.576 mole (Round n to the nearest hundredth, hence n becomes 0.58 moles)

Thus, there are 0.58 moles are in 92.2 g Fe2O3