a 49.2 g sample of solid iron was heated from 16.2c to 58.9c. what ws the energy change? solve for q (heat energy). iron has a specific heat value of. 4494

944.12 J

Explanation:

To solve for the energy change we use the equation Q=mc (Delta) t

Let's identify the variables we have:

m (mass) = 49.2 g

c (specific heat) =.4494

delta t (change in temp.) = final - initial = 58.9-16.2 = 42.7 degrees Celsius

Q = (49.2) (.4494) (42.7)

= 944.12 J