Given the following heats of combustion: C2H2 (g) = - 1300 kJ/mole, H2 (g) = - 286 kJ/mole, C2H6 (g) = - 1560 kJ/mole, Calculate the enthalpy change for the following reaction C2H2 (g) + 2H2 (g) → C2H6 (g)

a. - 312 kJ

b. - 26 kJ

c. + 312 kJ

d. - 26 kJ

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Guest

29 May, 12:26

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Answers (1)

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Kade Heath · Answer 1

Answer is A.

First plug in the designated enthalphy values for each Then solve for the equation as you would an algebra problem

Given the following heats of combustion: C2H2 (g) = - 1300 kJ/mole, H2 (g) = - 286 kJ/mole, C2H6 (g) = - 1560 kJ/mole, Calculate the enthalpy change for the following reaction C2H2 (g) + 2H2 (g) → C2H6 (g)a. - 312 kJb. - 26 kJc. + 312 kJd. - 26 kJ