What is the volume of 4.40 grams of CO2 at STP?

First, use formula, number of mole = given weight / molecular weight

given, weight of Carbon dioxide = 4.4 g

as we know, molecular weight of CO2 = atomic mass of C + 2 * atomic mass of O

we know, atomic mass of oxygen, {e. g., O} is 16g/mol

and atomic mass of carbon {e. g., C} is 12g/mol

so, molecular mass of CO2 = 12 + 2 * 16 = 12 + 32 = 44g/mol

now, number of mole = 4.4/44 = 0.1

A basic concept is that, 1 mole of an ideal gas at STP occupied 22. 4L volume.

so, 0.1 mole of CO2 occupied 22.4 * 0.1 = 2.24L volume at STP { standard temperature and pressure}.

the answer should be 2.24L