How much heat is needed warm 65.34 g of water from 18.43 to 21.75

Given that

Mass of water = 65.34 g

Amount of heat = mass of water * specific heat (temperature change

)

= 65.34 g * 4.184 J / g-C (21.75-18.43) C

= 907.63 J

= 0.908 KJ

And

1 cal = 4.186798 J

907.63 J * 1 cal / 4.186798 J = 216.78 cal

Or0.218 kcal