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12 November, 20:17

An unknown compound is discovered in a raid on a terrorist organization; it is believed that the compound is Sarin. When a 10.0-gram sample of this compoun is completely combusted, 15.6 g CO2 and 6.4 g H20 are produced, along with other combustion products. Using numerical calculations, prove that this unknown compound can not be Sarin.

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  1. 12 November, 22:24
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    Given:

    Mass of the unknown compound (believed to be Sarin) = 10.0 g

    Mass of CO2 produced = 15.6 g

    Mass of H2O produced = 6.4 g

    To determine:

    If the unknown compound is Sarin

    Explanation:

    The molecular formula for Sarin is: C₄H₁₀FO₂P

    Based on stoichiometry the C:H ratio = 4:10 i. e 2:5

    Now, from the combustion dа ta:

    # moles of CO2 produced = # moles of C present in the unknown sample

    Similarly, (# moles of H2O produced) * 2 = # moles of H present in the unknown sample

    # moles of CO2 = 15.6 g/44 g. mol-1 = 0.354 moles

    # moles of H2O = (6.4 g / 18 g. mol-1) * 2 = 0.711 moles

    The C:H ratio = 0.354 : 0.711 = 1:2

    Ans: Since the C:H ratio does not match the actual stoichiometry based on the molecular formula, the unknown compound is not Sarin.
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