What are the concentrations of Cu2+, NH3, and Cu (NH3) 42 + at equilibrium when 18.8 g of Cu (NO3) 2 is added to 1.0 L of a 0.800 M solution of aqueous ammonia? Assume that there is no volume change upon the addition of the solid, and that the reaction goes to completion and forms Cu (NH3) 42+.

Question

Chemistry

Athena Irwin

23 February, 19:25

What are the concentrations of Cu2+, NH3, and Cu (NH3) 42 + at equilibrium when 18.8 g of Cu (NO3) 2 is added to 1.0 L of a 0.800 M solution of aqueous ammonia? Assume that there is no volume change upon the addition of the solid, and that the reaction goes to completion and forms Cu (NH3) 42+.

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Mckinley Morse · Answer 1

Cu (NO₃) ₂ + 4NH₃ = Cu (NH₃) ₄²⁺ + 2 NO₃⁻

187.5 gm 4M 1 M

187.5 gm reacts with 4 M ammonia

18.8 g reacts with. 4 M ammonia

ammonia remaining left after reaction

=.8 M -.4 M =.4 M.

187.5 gm reacts with 4 M ammonia to form 1 M Cu (NH₃) ₄²⁺

18.8 g reacts with. 4 M ammonia to form 0.1 M Cu (NH₃) ₄²⁺

At equilibrium, the concentration of Cu²⁺ will be zero.

concentration of ammonia will be. 4 M

concentration of Cu (NH₃) ₄²⁺ formed will be 0.1 M