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10 January, 16:21

g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass. Must show your work on scratch paper to receive credit.

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  1. 10 January, 20:19
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    The empirical formula for the compound is C3H4O3

    Explanation:

    The following data were obtained from the question:

    Carbon (C) = 40.92%

    Hydrogen (H) = 4.58%

    Oxygen (O) = 54.50%

    The empirical formula for the compound can be obtained as follow:

    C = 40.92%

    H = 4.58%

    O = 54.50%

    Divide by their molar mass

    C = 40.92/12 = 3.41

    H = 4.58/1 = 4.58

    O = 54.50/16 = 3.41

    Divide by the smallest i. e 3.41

    C = 3.41/3.41 = 1

    H = 4.58/3.41 = 1.3

    O = 3.41/3.41 = 1

    Multiply through by 3 to express in whole number

    C = 1 x 3 = 3

    H = 1.3 x 3 = 4

    O = 1 x 3 = 3

    The empirical formula for the compound is C3H4O3
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