Ask Question
12 January, 08:00

When a 3.00 g 3.00 g sample of KBr KBr is dissolved in water in a calorimeter that has a total heat capacity of 1.36 kJ ⋅ K - 1, 1.36 kJ⋅K-1, the temperature decreases by 0.370 K. 0.370 K. Calculate the molar heat of solution of KBr. KBr.

+3
Answers (1)
  1. 12 January, 09:37
    0
    Molar heat of solution of KBr is 20.0kJ/mol

    Explanation:

    Molar heat of solution is defined as the energy released (negative) or absorbed (Positive) per mole of solute being dissolved in solvent.

    The dissolution of KBr is:

    KBr → K⁺ + Br⁻

    In the calorimeter, the temperature decreases 0.370K, that means the solution absorbes energy in this process. The energy is:

    q = 1.36kJK⁻¹ * 0.370K

    q = 0.5032kJ

    Moles of KBr in 3.00g are:

    3.00g * (1mol / 119g) = 0.0252moles

    Thus, molar heat of solution of KBr is:

    0.5032kJ / 0.0252moles = 20.0kJ/mol
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “When a 3.00 g 3.00 g sample of KBr KBr is dissolved in water in a calorimeter that has a total heat capacity of 1.36 kJ ⋅ K - 1, 1.36 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers