A flexible container has 5.00 L of nitrogen gas at 298 K. If the temperature is increased to 333K, what will the new volume of that sample of nitrogen?

0.179 L

0.223 L

4.47 L

5.59 L

Givens

V1 = 5.00 L V2 = ? T1 = 298k T2 = 333k

Formula

V1/T1 = V2/T2

Note: this will only work if the pressure is constant.

Solution

5.00L / 298 K = x / 333 Multiply both sides by 333 K

5.00 * 333 / 298 = x 333 / 333

5.59 L = V2