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10 May, 01:57

An evacuated reaction vessel is filled with 0.800 atm of N₂ and 1.681 atm of Br₂. When equilibrium is established according to the reaction below, there are 1.425 atm of Br₂ remaining in the vessel. What is the equilibrium partial pressure of NBr₃? 2 NBr₃ (g) ⇌ N₂ (g) + 3 Br₂ (g)

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  1. 10 May, 04:03
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    the equilibrium partial pressure of NBr₃ is 0.1707 atm

    the equilibrium partial pressure of NBr₃ is 0.1707 atm

    the equilibrium partial pressure of NBr₃ is 0.1707 atm

    Explanation:

    2 NBr₃ (g) ⇌ N₂ (g) + 3 Br₂ (g)

    initial atm 0.80 1.681

    Change atm 2x - x - 3x

    equlibrium atm 2x 0.80 - x 1.681 - 3x

    At equilibrium the Br₂ (g) remaining 1.425atm

    Therefore,

    1.681atm - 3x = 1.425atm

    3x = 0.256

    x = 0.0853

    Therefore, the equilibrium partial pressure of 2NBr₃ (g) is 2x

    = 2 * 0.0853

    = 0.1707 atm

    the equilibrium partial pressure of NBr₃ is 0.1707 atm
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